English
Karnataka Board PUCPUC Science Class 11

Visible Light Passing Through a Circular Hole Forms a Diffraction Disc of Radius 0.1 Mm on a Screen. If an X-ray is Passed Through the Same Setup, the Radius of the Diffraction Disc Will Be

Advertisements
Advertisements

Question

Visible light passing through a circular hole forms a diffraction disc of radius 0.1 mm on a screen. If an X-ray is passed through the same setup, the radius of the diffraction disc will be

Options

  • zero

  • < 0.1 mm

  • 0.1 mm

  • > 0.1 m

MCQ
Advertisements

Solution

< 0.1 mm

Radius of the diffraction disc is directly proportional to the wavelength of the light used for the given hole. We know that the wavelength of an X-ray is less than the wavelength of visible light. If an X-ray is passed through the same setup, the radius of the diffraction disc will be less than 0.1 m.

shaalaa.com
  Is there an error in this question or solution?
Chapter 44: X-rays - MCQ [Page 394]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 44 X-rays
MCQ | Q 14 | Page 394

RELATED QUESTIONS

Name the electromagnetic radiations used for (a) water purification, and (b) eye surgery.


State Moseley's law


Name the subjective property of light related to its wavelength.


What is the range of the wavelength of the following electromagnetic waves?

(a) Ultraviolet


How are X-rays produced?


Can X-rays be used for photoelectric effect?


Can X-rays be polarised?


X-ray and visible light travel at the same speed in vacuum. Do they travel at the same speed in glass?


50% of the X-ray coming from a Coolidge tube is able to pass through a 0.1 mm thick aluminium foil. The potential difference between the target and the filament is increased. The thickness of the aluminium foil that will allow 50% of the X-ray to pass through will be


For a given material, the energy and wavelength of characteristic X-rays satisfy
(a) E(Kα) > E(Kβ) > E(Kγ)
(b) E(Mα) > E(Lα) > E(Kα)
(c) λ(Kα) > λ(Kβ) > λ(Kγ)
(d) λ(Mα) > λ(Lα) > λ(Kα).


The electric current in an X-ray tube (from the target to the filament) operating at 40 kV is 10 mA. Assume that on an average, 1% of the total kinetic energy of the electron hitting hte target are converted into X-rays.
(a) What is the total power emitted as X-rays and (b) how much heat is produced in the target every second?


The wavelengths of Kα and Lα X-rays of a material are 21.3 pm and 141 pm respectively. Find the wavelength of Kβ X-ray of the material.

(Use Planck constant h = 6.63 × 10-34 Js= 4.14 × 10-15 eVs, speed of light c = 3 × 108 m/s.)


Name the scientist who discovered Ultraviolet rays


Gamma rays D C Visible light B A

The above table shows different parts of the electromagnetic spectrum.
(a)    Identify the parts of the spectrum marked as A, B, C and D.
(b)    Which of the radiations A or B has the higher frequency?
(c)    State two properties which are common to all parts of the electromagnetic spectrum.
(d)    Name one source of each of the radiation of electromagnetic spectrum.
(e)    Name one detector for each of the radiation.
(f)    Name one use of each of the radiation.


Identify the part of the electromagnetic spectrum used in
(i) radar and
(ii) eye surgery. Write their frequency range.


Give one use of electromagnetic radiation in Microwaves.


Answer briefly.

Why light waves travel in a vacuum whereas sound waves cannot?


Light of wavelength `3500A` is incident on two metals A and B whose work functions are 3.2 eV and 1.9 eV respectively. Which metal will emit photoelectrons?


Why does microwave oven heats up a food item containing water molecules most efficiently?


Electromagnetic waves with wavelength

  1. λ1 is suitable for radar systems used in aircraft navigation.
  2. λ2 is used to kill germs in water purifiers.
  3. λ3 is used to improve visibility in runways during fog and mist conditions.

Identify and name the part of the electromagnetic spectrum to which these radiations belong. Also arrange these wavelengths in ascending order of their magnitude.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×