Advertisements
Advertisements
Question
Using Heron’s formula, find the area of a triangle whose sides are 1.8 m, 8 m, 8.2 m
Advertisements
Solution
Here a = 1.8 m, b = 8 m, c = 8.2 m
s = `("a" + "b" + "c")/2`
= `((1.8 + 8 + 8.2)"m")/2`
= `18/2`
= 9 m
s – a = 9 – 1.8 = 7.2 m
s – b = 9 – 8 = 1 m
s – c = 9 – 8.2 m = 0.8
Area of triangle
= `sqrt("s"("s" - "a")("s" - "b")("s" - "c"))`
= `sqrt(9 xx 7.2 xx 1 xx 0.8)`
= `sqrt(9 xx 5.76)`
= `sqrt9 xx sqrt(576/100)`
= `3 xx 24/10`
= 3 × 2.4
= 7.2 m2
∴ Area of the triangle = 7.2 sq.m
APPEARS IN
RELATED QUESTIONS
The perimeter of a triangle is 300 m. If its sides are in the ratio 3 : 5 : 7. Find the area of the triangle ?
The perimeter of a triangular field is 240 dm. If two of its sides are 78 dm and 50 dm, find the length of the perpendicular on the side of length 50 dm from the opposite vertex.
Find the area of an isosceles triangle having the base x cm and one side y cm.
Determine whether the sets of points are collinear?
`(-1/2, 3), (-5, 6) and (-8, 8)`
If the points A(– 3, 9), B(a, b) and C(4, – 5) are collinear and if a + b = 1, then find a and b
The area of triangle formed by the points (− 5, 0), (0, – 5) and (5, 0) is
The area of a triangle is 5 sq. units. Two of its vertices are (2, 1) and (3, −2). The third vertex is (x, y) where y = x + 3. Find the coordinates of the third vertex.
Using Heron’s formula, find the area of a triangle whose sides are 10 cm, 24 cm, 26 cm
From a point in the interior of an equilateral triangle, perpendiculars are drawn on the three sides. The lengths of the perpendiculars are 14 cm, 10 cm and 6 cm. Find the area of the triangle.
Find the area of a parallelogram given in figure. Also find the length of the altitude from vertex A on the side DC.
