Advertisements
Advertisements
प्रश्न
Using Heron’s formula, find the area of a triangle whose sides are 1.8 m, 8 m, 8.2 m
Advertisements
उत्तर
Here a = 1.8 m, b = 8 m, c = 8.2 m
s = `("a" + "b" + "c")/2`
= `((1.8 + 8 + 8.2)"m")/2`
= `18/2`
= 9 m
s – a = 9 – 1.8 = 7.2 m
s – b = 9 – 8 = 1 m
s – c = 9 – 8.2 m = 0.8
Area of triangle
= `sqrt("s"("s" - "a")("s" - "b")("s" - "c"))`
= `sqrt(9 xx 7.2 xx 1 xx 0.8)`
= `sqrt(9 xx 5.76)`
= `sqrt9 xx sqrt(576/100)`
= `3 xx 24/10`
= 3 × 2.4
= 7.2 m2
∴ Area of the triangle = 7.2 sq.m
APPEARS IN
संबंधित प्रश्न
The perimeter of a triangular field is 240 dm. If two of its sides are 78 dm and 50 dm, find the length of the perpendicular on the side of length 50 dm from the opposite vertex.
Look at the measures shown in the adjacent figure and find the area of ☐ PQRS.
Find the areas of the given plot. (All measures are in metres.)
Find the area of the triangle formed by the points
(–10, –4), (–8, –1) and (–3, –5)
If the points A(– 3, 9), B(a, b) and C(4, – 5) are collinear and if a + b = 1, then find a and b
Using Heron’s formula, find the area of a triangle whose sides are 10 cm, 24 cm, 26 cm
Find the area of the unshaded region
An isosceles right triangle has area 8 cm2. The length of its hypotenuse is ______.
If the side of a rhombus is 10 cm and one diagonal is 16 cm, the area of the rhombus is 96 cm2.
Find the area of a parallelogram given in figure. Also find the length of the altitude from vertex A on the side DC.
