Advertisements
Advertisements
Question
Two resistors having 2Ω and 3Ω resistance are connected—(i) in series, and (ii) in parallel. Find the equivalent resistance in each case.
Advertisements
Solution
Given: R1 = 2 Ω, R2 = 3 Ω
(i) In series : Equivalent resistance R = R1 + R2
or R = 2 + 3 = 5 Ω
(ii) In parallel : Equivalent resistance R = `("R"_1"R"_2)/("R"_1 + "R"_2)`
or R = `(2 xx 3)/(2 + 3) = 6/5 = 1.2 Omega`
APPEARS IN
RELATED QUESTIONS
How does the resistance of a pure metal change if its temperature decreases?
How does the resistance of a wire change when:
its length is tripled?
State how are the two resistors joined with a battery when same current flows in each resistor.
A graph is plotted taking p.d. along y-axis and electric current along x-axis. Name the physical quantity that represents the slope of this graph (Fig.).
How will you oonnect five resistors, each of the value one ohm, to obtain an equivalent resistance of 0.2 `Omega`
Write an expression for the resistance of a conducting wire in terms of its length and area of cross-section.
How does the resistivity of an alloy such as constantace depends on temperature.
Calculate the quantity of heat that will be produced in a coil of resistance 75 Ω if a current of 2A is passed through it for 2 minutes.
When a 4 Ω resistor is connected across the terminals of a 2 V battery, the number of coulombs passing through the resistor per second is:
