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Question
Two resistors having 2Ω and 3Ω resistance are connected—(i) in series, and (ii) in parallel. Find the equivalent resistance in each case.
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Solution
Given: R1 = 2 Ω, R2 = 3 Ω
(i) In series : Equivalent resistance R = R1 + R2
or R = 2 + 3 = 5 Ω
(ii) In parallel : Equivalent resistance R = `("R"_1"R"_2)/("R"_1 + "R"_2)`
or R = `(2 xx 3)/(2 + 3) = 6/5 = 1.2 Omega`
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