Advertisements
Advertisements
Question
Two resistors A and B of 4 Ω and 6 Ω, respectively are connected in parallel. The combination is connected across a 6 volt battery of negligible resistance. Calculate the power dissipated in each resistor.
Advertisements
Solution
The effective resistance of 4 Ω and 6 Ω in parallel
The power dissipated in 4 Ω
P = `(6 xx 6)/4`
= 9 W
Power dissipated in 6 Ω
P = `(6 xx 6)/6`
= 6 W
B = 6 W
APPEARS IN
RELATED QUESTIONS
What is consumed using different electrical appliances, for which electricity bills are paid?
Electrical power P is given by the expression P = (Q × V) ÷ time. What do the symbols Q and V represent?
An electric bulb is rated ‘100 W, 250 V’. What information does this convey?
What is the order of current drawn by appliances connected to the ‘light circuit’ of a household?
How does the heat produced by die passage of current in a metallic wire depend on the resistance of the wire.
Two resistances R1 = 4Ω and R2 = 6Ω are connected in series. The combination is connected with a battery of e.m.f. 6V and negligible resistance. Calculate:
(i) the heat produced per minute in each resistor,
(ii) the power supplied by the battery.
A bulb is connected to a battery of e.m.f. 6V and internal resistance 2Ω A steady current of 0.5A flows through the bulb. Calculate the total energy supplied by the battery in 10 minutes.
Unit of electric power may also be expressed as:
Electric power is inversely proportional to ____________.
A family uses 8 kW of power. Direct solar energy is incident on the horizontal surface at an average rate of 200 W per square meter. If 20% of this energy can be converted to useful electrical energy, how large an area is needed to supply 8 kW?
