Advertisements
Advertisements
Question
A bulb is connected to a battery of e.m.f. 6V and internal resistance 2Ω A steady current of 0.5A flows through the bulb. Calculate the heat energy dissipated in the bulb in 10 minutes.
Advertisements
Solution
Given: E = 6V, r = 2Ω, i = 0.5A, t = 10 minute = 10 × 60s = 600s.
The heat energy dissipated in the bulb = i2Rt
= (0.5)2 × 10 × 600 = 1500 J
RELATED QUESTIONS
Which of the following terms does not represent electrical power in a circuit?
Which uses more energy: a 250 W TV set in 1 hour or a 1200 W toaster in 10 minutes?
Calculate the resistance of an electric bulb which allows a 10 A current when connected to a 220 V power source.
A coil of copper wire is connected to a galvanometer. What would happen if a bar magnet is:
(i) Pushed into the coil with its north pole entering first?
(ii) Held at rest inside the coil?
(iii) Pulled out again?
Point out two main disadvantages of ‘Tree System’.
An electric bulb is marked 100 W, 230 V. What does this mean?
Using a long extension cord in which each conductor has a resistance of 8Ω, a bulb marked as '100 W, 200 V' is connected to a 220 V dc supply of negligible internal resistance as shown in the figure. The power delivered to the bulb is ______ W.
