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Karnataka Board PUCPUC Science Class 11

Two molecules of a gas have speeds of 9 × 10 6 ms−1 and 1 × 106 ms−1, respectively. What is the root mean square speed of these molecules? - Physics

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Question

Two molecules of a gas have speeds of 9 × 10 6 ms−1 and 1 × 106 ms−1, respectively. What is the root mean square speed of these molecules?

Short/Brief Note
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Solution

For n-molecules, we know that

`v_(rms) = sqrt((v_1^2 + v_2^2 + v_3^2 + ...... + v_n^2)/n`  .....`[(v_(rms) = "root mean"),("square velocity")]`

Where v1, v2, v3 ....... vn are individual velocities of n-molecules of the gas.

For two molecules,

`v_(rms) = sqrt((v_1^2 + v_2^2)/2`  ......[v1, v2, v3 ....... vn are individual velocity]

Given, `v_1 = 9 xx 10^6` m/s

And `v_2 = 1 xx 10^6` m/s

∴ `v_(rms) = sqrt(((9 xx 10^6)^2 + (1 xx 10^6)^2)/2`

= `sqrt((81 xx 10^12 + 1 xx 10^12)/2`

= `sqrt(((81 + 1) xx 10^12)/2`

= `sqrt((82 xx 10^12)/2`

= `sqrt(41) xx 10^6` m/s

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Chapter 13: Kinetic Theory - Exercises [Page 94]

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NCERT Exemplar Physics [English] Class 11
Chapter 13 Kinetic Theory
Exercises | Q 13.17 | Page 94

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