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Question
Two blocks each having a mass of 3⋅2 kg are connected by a wire CD and the system is suspended from the ceiling by another wire AB (See following figure). The linear mass density of the wire AB is 10 g m−1 and that of CD is 8 g m−1. Find the speed of a transverse wave pulse produced in AB and CD.

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Solution
Given,
\[m_1 = m_2 = 3 . 2 kg\]
Linear mass density of wire AB = 10 gm−1 = 0.01 kgm−1
Linear mass density of wire CD = 8 gm−1 = 0.008 kgm−1
For string CD, velocity is defined as
\[v = \sqrt{\left( \frac{T}{m} \right)}\]
Here, T is the tension and m is the mass per unit length.
For string CD,
\[T = 3 . 2 \times g\]
Thus, we have:
\[v = \sqrt{\frac{\left( 3 . 2 \times 10 \right)}{0 . 008}}\]
\[= \sqrt{\frac{\left( 32 \times {10}^3 \right)}{8}}\]
\[= 2 \times 10\sqrt{10}\]
\[= 20 \times 3 . 14 \approx 63 \text{ s }\]
For string AB,
\[T = 2 \times 3 . 2g = 64 N\]
Thus, we have:
\[v = \sqrt{\left( \frac{T}{m} \right)}\]
\[= \sqrt{\left( \frac{64}{0 . 01} \right)} = \sqrt{6400}\]
\[= 80 \text{ m/s }\]
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