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Question
Three resistors of 6Ω, 4Ω and 4Ω are connected together so that the total resistance is 8Ω. Draw a diagram to show this arrangement and give reason to justify your answer.
Sum
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Solution
In parellel,
`1/"R'" = 1/4 + 1/4`
R' = `4/2` = 2Ω
In series, R = R' + R"
2Ω + 6Ω = 8Ω
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