Advertisements
Advertisements
Question
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Advertisements
Solution
We have, the sum of first n natural numbers = `n^2/2 + n/2`
Factorisation of given expression = `1/2(n^2 + n) = 1/2n(n + 1)` ...[Taking n as common]
APPEARS IN
RELATED QUESTIONS
Expand: (3x + 4y)(3x - 4y)
Expand 4p2 – 25q2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/9 - y^2/25`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(x + y)4 – (x – y)4
Verify the following:
(a + b + c)(a2 + b2 + c2 – ab – bc – ca) = a3 + b3 + c3 – 3abc
Find the value of a, if 9a = 762 – 672
