Advertisements
Advertisements
Question
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(6x + 7y)(6x – 7y)
Advertisements
Solution
(6x + 7y)(6x – 7y)
Substituting a = 6x and b = 7y
In (a + b)(a – b) = a2 – b2, we get
(6x + 7y)(6x – 7y) = (6x)2 – (7y)2
= 62x2 – 72y2
(6x + 7y)(6x – 7y) = 36x2 – 49y2
APPEARS IN
RELATED QUESTIONS
Choose the right answers from the option:
The difference of the squares, (612 – 512 ) is equal to ______.
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
z2 – 16
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
25a2 – 49b2
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
(5 + 20)(–20 – 5) = ?
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
28ay2 – 175ax2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the expression and divide them as directed:
(3x2 – 48) ÷ (x – 4)
