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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 7

Factorise: 4x2 – 9y2 - Mathematics

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Question

Factorise: 4x2 – 9y2

Sum
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Solution

4x2 – 9y2 = 22x2 – 32y2 = (2x)2 – (3y)2

Substituting a = 2x and b = 3y in

(a2 – b2) = (a + b)(a – b), we have

(2x)2 – (3y)2 = (2x + 3y)(2x – 3y)

∴ Factors of 4x2 – 9y2 are (2x + 3y) and (2x – 3y)

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Chapter 3: Algebra - Exercise 3.3 [Page 69]

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Samacheer Kalvi Mathematics - Term 3 [English] Class 7 TN Board
Chapter 3 Algebra
Exercise 3.3 | Q 2 | Page 69
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