Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(6x + 7y)(6x – 7y)
Advertisements
उत्तर
(6x + 7y)(6x – 7y)
Substituting a = 6x and b = 7y
In (a + b)(a – b) = a2 – b2, we get
(6x + 7y)(6x – 7y) = (6x)2 – (7y)2
= 62x2 – 72y2
(6x + 7y)(6x – 7y) = 36x2 – 49y2
APPEARS IN
संबंधित प्रश्न
Choose the right answers from the option:
The difference of the squares, (612 – 512 ) is equal to ______.
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
z2 – 16
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`y^3 - y/9`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
Factorise the expression and divide them as directed:
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Find the value of a, if 8a = 352 – 272
Find the value of `(198 xx 198 - 102 xx 102)/96`
