Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(6x + 7y)(6x – 7y)
Advertisements
उत्तर
(6x + 7y)(6x – 7y)
Substituting a = 6x and b = 7y
In (a + b)(a – b) = a2 – b2, we get
(6x + 7y)(6x – 7y) = (6x)2 – (7y)2
= 62x2 – 72y2
(6x + 7y)(6x – 7y) = 36x2 – 49y2
APPEARS IN
संबंधित प्रश्न
Evaluate the following, using suitable identity
297 × 303
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
The value of p for 512 – 492 = 100p is 2.
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Using suitable identities, evaluate the following.
(132)2 – (68)2
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(a – b)2 – (b – c)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(x + y)4 – (x – y)4
Factorise the expression and divide them as directed:
(3x4 – 1875) ÷ (3x2 – 75)
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
