Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(6x + 7y)(6x – 7y)
Advertisements
उत्तर
(6x + 7y)(6x – 7y)
Substituting a = 6x and b = 7y
In (a + b)(a – b) = a2 – b2, we get
(6x + 7y)(6x – 7y) = (6x)2 – (7y)2
= 62x2 – 72y2
(6x + 7y)(6x – 7y) = 36x2 – 49y2
APPEARS IN
संबंधित प्रश्न
Factorise: 4x2 – 9y2
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(a – b)2 – (b – c)2
Factorise the expression and divide them as directed:
(x3 + x2 – 132x) ÷ x(x – 11)
Factorise the expression and divide them as directed:
(3x2 – 48) ÷ (x – 4)
Find the value of a, if 8a = 352 – 272
Find the value of `(6.25 xx 6.25 - 1.75 xx 1.75)/(4.5)`
