Advertisements
Advertisements
प्रश्न
Using identity, find the value of (1.9) × (2.1)
Advertisements
उत्तर
(1.9) × (2.1) = (2 – 0.1) × (2 + 0.1)
Substituting a = 2 and b = 0.1 in
(a – b)(a + b) = a2 – b2 we have
(2 – 0.1)(2 + 0.1) = 22 – (0.1)2
(1.9) × (2.1) = 4 – 0.01
(9.9)(2.1) = 3.99
APPEARS IN
संबंधित प्रश्न
Expand: 102 x 98
(x + 4) and (x – 5) are the factors of ___________
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
z2 – 16
Using suitable identities, evaluate the following.
(35.4)2 – (14.6)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Factorise the expression and divide them as directed:
(x2 – 22x + 117) ÷ (x – 13)
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
