Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Advertisements
उत्तर
We have,
16x4 – 81 = (4x2)2 – 92
= (4x2 + 9)(4x2 – 9)
= (4x2 + 9)[(2x)2 – 32]
= (4x2 + 9)(2x + 3)(2x – 3)
APPEARS IN
संबंधित प्रश्न
Simplify (5x – 3y)2 – (5x + 3y)2
Using suitable identities, evaluate the following.
(35.4)2 – (14.6)2
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
1331x3y – 11y3x
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – (3y + z)2
Factorise the expression and divide them as directed:
(x3 + x2 – 132x) ÷ x(x – 11)
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Find the value of `(198 xx 198 - 102 xx 102)/96`
