Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Advertisements
उत्तर
We have,
p5 – 16p = p(p4 – 16) = p[(p2)2 – 42]
= p(p2 + 4)(p2 – 4)
= p(p2 + 4)(p2 – 22)
= p(p2 + 4)(p + 2)(p – 2)
APPEARS IN
संबंधित प्रश्न
Expand 4p2 – 25q2
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
a2 – b2 = (a + b) ______.
Using suitable identities, evaluate the following.
9.8 × 10.2
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
4x2 – 49y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
49x2 – 36y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
