Advertisements
Advertisements
प्रश्न
The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x – 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?
Advertisements
उत्तर
We have, the base and the corresponding height of a parallelogram are (2x + 3) units and (2x – 3) units, respectively.
∵ Area of a parallelogram = Base × Height
= (2x + 3) × (2x – 3)
= (2x)2 – (3)2 ...[∵ (a + b)(a – b) = a2 – b2]
= (4x2 – 9) sq.units
Now, If x = 30.
Then, the area of the parallelogram = 4 × (30)2 – 9
= 3600 – 9
= 3591 sq.units
APPEARS IN
संबंधित प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(1 + 3b)(3b – 1)
(a + b)(a – b) = a2 – b2
Using suitable identities, evaluate the following.
9.8 × 10.2
Using suitable identities, evaluate the following.
(35.4)2 – (14.6)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
a4 – (a – b)4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the expression and divide them as directed:
(3x2 – 48) ÷ (x – 4)
Factorise the expression and divide them as directed:
(x4 – 16) ÷ x3 + 2x2 + 4x + 8
Find the value of a, if 9a = 762 – 672
