Advertisements
Advertisements
प्रश्न
The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x – 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?
Advertisements
उत्तर
We have, the base and the corresponding height of a parallelogram are (2x + 3) units and (2x – 3) units, respectively.
∵ Area of a parallelogram = Base × Height
= (2x + 3) × (2x – 3)
= (2x)2 – (3)2 ...[∵ (a + b)(a – b) = a2 – b2]
= (4x2 – 9) sq.units
Now, If x = 30.
Then, the area of the parallelogram = 4 × (30)2 – 9
= 3600 – 9
= 3591 sq.units
APPEARS IN
संबंधित प्रश्न
Choose the right answers from the option:
The difference of the squares, (612 – 512 ) is equal to ______.
Find the value of (x – y)(x + y)(x2 + y2)
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Using suitable identities, evaluate the following.
(132)2 – (68)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`y^3 - y/9`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
Factorise the expression and divide them as directed:
(x3 + x2 – 132x) ÷ x(x – 11)
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
