Advertisements
Advertisements
प्रश्न
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Advertisements
उत्तर
Given X = a2 – 1
Y = 1 – b2
X + Y = (a2 – 1) + (1 – b2)
= a2 – 1 + 1 – b2
We know the identity that a2 – b2 = (a + b)(a – b)
∴ X + Y = (a + b)(a – b)
APPEARS IN
संबंधित प्रश्न
(x + 4) and (x – 5) are the factors of ___________
Evaluate the following, using suitable identity
990 × 1010
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
3a2b3 – 27a4b
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
1331x3y – 11y3x
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
Factorise the expression and divide them as directed:
(x3 + x2 – 132x) ÷ x(x – 11)
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
Verify the following:
(a + b + c)(a2 + b2 + c2 – ab – bc – ca) = a3 + b3 + c3 – 3abc
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
