Advertisements
Advertisements
प्रश्न
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Advertisements
उत्तर
Given X = a2 – 1
Y = 1 – b2
X + Y = (a2 – 1) + (1 – b2)
= a2 – 1 + 1 – b2
We know the identity that a2 – b2 = (a + b)(a – b)
∴ X + Y = (a + b)(a – b)
APPEARS IN
संबंधित प्रश्न
(x + 4) and (x – 5) are the factors of ___________
Factorise: 4x2 – 9y2
(a + b)(a – b) = a2 – b2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
49x2 – 36y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – (3y + z)2
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
The radius of a circle is 7ab – 7bc – 14ac. Find the circumference of the circle. `(pi = 22/7)`
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
