Advertisements
Advertisements
प्रश्न
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
Advertisements
उत्तर
We have,
pq2a = (4pq + 3q)2 – (4pq – 3q)2
⇒ [(4pq + 3q) + (4pq – 3q)][(4pq + 3q) – (4pq – 3q)] ...[Using the identity, a2 – b2 = (a + b)(a – b)]
⇒ (4pq + 3q + 4pq – 3q)(4pq + 3q – 4pq + 3q)
⇒ 8pq × 6q
⇒ pq2a = 48pq2
⇒ `a = (48pq^2)/(pq^2)`
⇒ a = 48
APPEARS IN
संबंधित प्रश्न
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
25a2 – 49b2
Simplify using identities
(3p + q)(3p – q)
Simplify (5x – 3y)2 – (5x + 3y)2
Using suitable identities, evaluate the following.
(35.4)2 – (14.6)2
Using suitable identities, evaluate the following.
(69.3)2 – (30.7)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Factorise the expression and divide them as directed:
(x4 – 16) ÷ x3 + 2x2 + 4x + 8
The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x – 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
