Advertisements
Advertisements
प्रश्न
Find the value of a, if pqa = (3p + q)2 – (3p – q)2
Advertisements
उत्तर
We have,
pqa = (3p + q)2 – (3p – q)2
⇒ pqa = [(3p + q) + (3p – q)][(3p + q) – (3p – q)] ...[Using the identity, a2 – b2 = (a + b)(a – b)]
⇒ pqa = [(3p + q + 3p – q)][3p + q – 3p + q]
⇒ pqa = 6p × 2q
⇒ `a = (6p xx 2q)/(pq) = ((6 xx 2)pq)/(pq)`
⇒ a = 12
APPEARS IN
संबंधित प्रश्न
(x + 4) and (x – 5) are the factors of ___________
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(p + 2)(p – 2)
672 – 372 = (67 – 37) × ______ = ______.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
a4 – (a – b)4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – (3y + z)2
Factorise the expression and divide them as directed:
(3x2 – 48) ÷ (x – 4)
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
