Advertisements
Advertisements
प्रश्न
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
Advertisements
उत्तर
Taking L.H.S. = (ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab)
= [(ab)2 – (bc)2] + [(bc)2 – (ca)2] + [(ca)2 – (ab)2] ...[Using the identity, (a + b)(a – b) = a2 – b2]
= a2b2 – b2c2 + b2c2 – c2a2 + c2a2 – a2b2
= 0
= R.H.S. ...[Cancelling the like terms having opposite signs]
Hence verified.
APPEARS IN
संबंधित प्रश्न
Expand: (3x + 4y)(3x - 4y)
The product of (x + 5) and (x – 5) is ____________
(a + b)(a – b) = a2 – b2
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
1331x3y – 11y3x
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the expression and divide them as directed:
(x4 – 16) ÷ x3 + 2x2 + 4x + 8
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
