Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
49x2 – 36y2
बेरीज
Advertisements
उत्तर
We have,
49x2 – 36y2 = (7x)2 – (6y)2
= (7x – 6y)(7x + 6y)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
a2 – b2 = (a + b) ______.
672 – 372 = (67 – 37) × ______ = ______.
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Multiply the following:
(a2 – b2), (a2 + b2)
Using suitable identities, evaluate the following.
(35.4)2 – (14.6)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
28ay2 – 175ax2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
Find the value of a, if 9a = 762 – 672
