Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Advertisements
उत्तर
We have,
`(x^3y)/9 - (xy^3)/16 = xy(x^2/9 - y^2/16)`
= `xy[(x/3)^2 - (y/4)^2]`
= `xy(x/3 + y/4)(x/3 - y/4)`
APPEARS IN
संबंधित प्रश्न
Factorise : 16p4 – 1
Factorise: 4x2 – 9y2
Find the value of (x – y)(x + y)(x2 + y2)
Simplify (5x – 3y)2 – (5x + 3y)2
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
1331x3y – 11y3x
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – y4 + x2 – y2
