Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Advertisements
उत्तर
We have,
`(x^3y)/9 - (xy^3)/16 = xy(x^2/9 - y^2/16)`
= `xy[(x/3)^2 - (y/4)^2]`
= `xy(x/3 + y/4)(x/3 - y/4)`
APPEARS IN
संबंधित प्रश्न
Expand: (3x + 4y)(3x - 4y)
(7x + 3)(7x – 4) = 49x2 – 7x – 12
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Using suitable identities, evaluate the following.
(339)2 – (161)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
25ax2 – 25a
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2 - y^2/100`
Factorise the expression and divide them as directed:
(x4 – 16) ÷ x3 + 2x2 + 4x + 8
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
