Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
Advertisements
उत्तर
(4 – mn)(mn + 4)
(4 – mn)(mn + 4) can be written as (4 – mn) (4 + mn = (4 + mn)(4 – mn)
Substituting a = 4 and b = mn
In (a + b)(a – b) = a2 – b2, we get
(4 + mn)(4 – mn) = 42 – (mn)2
= 16 – m2 n2
APPEARS IN
संबंधित प्रश्न
Factorise the following expressions
m2 + m – 72
(7x + 3)(7x – 4) = 49x2 – 7x – 12
Multiply the following:
(a2 – b2), (a2 + b2)
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 81
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – (3y + z)2
Factorise the expression and divide them as directed:
(x2 – 22x + 117) ÷ (x – 13)
Find the value of `(198 xx 198 - 102 xx 102)/96`
