Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
Advertisements
उत्तर
(4 – mn)(mn + 4)
(4 – mn)(mn + 4) can be written as (4 – mn) (4 + mn = (4 + mn)(4 – mn)
Substituting a = 4 and b = mn
In (a + b)(a – b) = a2 – b2, we get
(4 + mn)(4 – mn) = 42 – (mn)2
= 16 – m2 n2
APPEARS IN
संबंधित प्रश्न
Factorise the following expressions
m2 + m – 72
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
28ay2 – 175ax2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
25ax2 – 25a
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(a – b)2 – (b – c)2
Factorise the expression and divide them as directed:
(3x4 – 1875) ÷ (3x2 – 75)
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
Find the value of a, if 8a = 352 – 272
Find the value of a, if 9a = 762 – 672
