Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(1 + 3b)(3b – 1)
Advertisements
उत्तर
(1 + 3b)(3b – 1)
(1 + 3b)(3b – 1) can be written as (3b + 1)(3b – 1)
Substituting a = 3b and b = 1
In (a + b)(a – b) = a2 – b2, we get
(3b + 1)(3b – 1) = (3b)2 – 12
= 32 × b2 – 12
(3b + 1)(3b – 1) = 9b2 – 12
APPEARS IN
संबंधित प्रश्न
Evaluate the following, using suitable identity
990 × 1010
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
z2 – 16
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Find the value of (x – y)(x + y)(x2 + y2)
Multiply the following:
(a2 – b2), (a2 + b2)
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the expression and divide them as directed:
(x4 – 16) ÷ x3 + 2x2 + 4x + 8
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Verify the following:
(a + b + c)(a2 + b2 + c2 – ab – bc – ca) = a3 + b3 + c3 – 3abc
Verify the following:
(p – q)(p2 + pq + q2) = p3 – q3
