Advertisements
Advertisements
प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(1 + 3b)(3b – 1)
Advertisements
उत्तर
(1 + 3b)(3b – 1)
(1 + 3b)(3b – 1) can be written as (3b + 1)(3b – 1)
Substituting a = 3b and b = 1
In (a + b)(a – b) = a2 – b2, we get
(3b + 1)(3b – 1) = (3b)2 – 12
= 32 × b2 – 12
(3b + 1)(3b – 1) = 9b2 – 12
APPEARS IN
संबंधित प्रश्न
(x + 4) and (x – 5) are the factors of ___________
The product of (x + 5) and (x – 5) is ____________
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
3a2b3 – 27a4b
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 625
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Find the value of `(198 xx 198 - 102 xx 102)/96`
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
