Advertisements
Advertisements
प्रश्न
Verify the following:
(a2 – b2)(a2 + b2) + (b2 – c2)(b2 + c2) + (c2 – a2) + (c2 + a2) = 0
Advertisements
उत्तर
Taking L.H.S. = (a2 – b2)(a2 + b2) + (b2 – c2)(b2 + c2) + (c2 – a2) + (c2 + a2)
= (a4 – b4 + b4 – c4 + c4 – a4) ...[Using the identity, (a – b)(a + b) = a2 – b2]
= 0
= R.H.S.
Hence verified.
APPEARS IN
संबंधित प्रश्न
Choose the right answers from the option:
The difference of the squares, (612 – 512 ) is equal to ______.
Expand: (3x + 4y)(3x - 4y)
Evaluate the following, using suitable identity
297 × 303
Evaluate the following, using suitable identity
990 × 1010
Simplify using identities
(3p + q)(3p – q)
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
49x2 – 36y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – y4 + x2 – y2
Factorise the expression and divide them as directed:
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
