Advertisements
Advertisements
प्रश्न
Verify the following:
(a2 – b2)(a2 + b2) + (b2 – c2)(b2 + c2) + (c2 – a2) + (c2 + a2) = 0
Advertisements
उत्तर
Taking L.H.S. = (a2 – b2)(a2 + b2) + (b2 – c2)(b2 + c2) + (c2 – a2) + (c2 + a2)
= (a4 – b4 + b4 – c4 + c4 – a4) ...[Using the identity, (a – b)(a + b) = a2 – b2]
= 0
= R.H.S.
Hence verified.
APPEARS IN
संबंधित प्रश्न
Choose the right answers from the option:
The difference of the squares, (612 – 512 ) is equal to ______.
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(1 + 3b)(3b – 1)
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
25a2 – 49b2
a2 – b2 = (a + b) ______.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
4x2 – 49y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/9 - y^2/25`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(2p^2)/25 - 32q^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(x + y)4 – (x – y)4
Find the value of `(6.25 xx 6.25 - 1.75 xx 1.75)/(4.5)`
