Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(2p^2)/25 - 32q^2`
Advertisements
उत्तर
We have,
`(2p^2)/25 - 32q^2 = 2(p^2/25 - 16q^2)`
= `2[(p/5)^2 - (4q)^2]`
= `2(p/5 + 4q)(p/5 - 4q)`
APPEARS IN
संबंधित प्रश्न
Factorise: 4x2 – 9y2
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Simplify (5x – 3y)2 – (5x + 3y)2
a2 – b2 = (a + b) ______.
672 – 372 = (67 – 37) × ______ = ______.
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
4x2 – 49y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – y4 + x2 – y2
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x – 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
