Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(2p^2)/25 - 32q^2`
Advertisements
उत्तर
We have,
`(2p^2)/25 - 32q^2 = 2(p^2/25 - 16q^2)`
= `2[(p/5)^2 - (4q)^2]`
= `2(p/5 + 4q)(p/5 - 4q)`
APPEARS IN
संबंधित प्रश्न
The product of (x + 5) and (x – 5) is ____________
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
z2 – 16
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the expression and divide them as directed:
(x2 – 22x + 117) ÷ (x – 13)
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
The sum of (x + 5) observations is x4 – 625. Find the mean of the observations.
Verify the following:
(a2 – b2)(a2 + b2) + (b2 – c2)(b2 + c2) + (c2 – a2) + (c2 + a2) = 0
Find the value of `(6.25 xx 6.25 - 1.75 xx 1.75)/(4.5)`
