Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
4x2 – 49y2
Advertisements
उत्तर
We have,
4x2 – 49y2 = (2x)2 – (7y)2
= (2x – 7y)(2x + 7y)
APPEARS IN
संबंधित प्रश्न
The product of (x + 5) and (x – 5) is ____________
(7x + 3)(7x – 4) = 49x2 – 7x – 12
The value of p for 512 – 492 = 100p is 2.
Using suitable identities, evaluate the following.
(132)2 – (68)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
25ax2 – 25a
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
