Advertisements
Advertisements
प्रश्न
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Advertisements
उत्तर
We have, the sum of first n natural numbers = `n^2/2 + n/2`
Factorisation of given expression = `1/2(n^2 + n) = 1/2n(n + 1)` ...[Taking n as common]
APPEARS IN
संबंधित प्रश्न
Expand: (3x + 4y)(3x - 4y)
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(p + 2)(p – 2)
Using identity, find the value of (1.9) × (2.1)
Find the value of (x – y)(x + y)(x2 + y2)
Using suitable identities, evaluate the following.
(339)2 – (161)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
4x2 – 25y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/9 - y^2/25`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – (3y + z)2
Find the value of a, if 9a = 762 – 672
Find the value of `(6.25 xx 6.25 - 1.75 xx 1.75)/(4.5)`
