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प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 81
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उत्तर
We have,
y4 – 81 = (y2)2 – (9)2
= (y2 + 9)(y2 – 9)
= (y2 + 9)[(y)2 – (3)2]
= (y2 + 9)(y + 3)(y – 3)
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संबंधित प्रश्न
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
(a + b)(a – b) = a2 – b2
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Using suitable identities, evaluate the following.
9.8 × 10.2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/9 - y^2/25`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Verify the following:
(p – q)(p2 + pq + q2) = p3 – q3
Verify the following:
(a2 – b2)(a2 + b2) + (b2 – c2)(b2 + c2) + (c2 – a2) + (c2 + a2) = 0
