Advertisements
Advertisements
प्रश्न
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Advertisements
उत्तर
Given X = a2 – 1
Y = 1 – b2
X + Y = (a2 – 1) + (1 – b2)
= a2 – 1 + 1 – b2
We know the identity that a2 – b2 = (a + b)(a – b)
∴ X + Y = (a + b)(a – b)
APPEARS IN
संबंधित प्रश्न
Expand: 102 x 98
The pathway of a square paddy field has 5 m width and length of its side is 40 m. Find the total area of its pathway. (Note: Use suitable identity)
Find the value of (x – y)(x + y)(x2 + y2)
Using suitable identities, evaluate the following.
(35.4)2 – (14.6)2
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
8a3 – 2a
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
