Advertisements
Advertisements
प्रश्न
Evaluate the following, using suitable identity
990 × 1010
Advertisements
उत्तर
990 × 1010 = (1000 – 10)(1000 + 10)
Taking a = 1000 and b = 10, then
(a – b)(a + b) = a2 – b2 becomes
(1000 – 10)(1000 + 10) = 10002 – 102
990 × 1010 = 1000000 – 100
990 × 1010 = 999900
APPEARS IN
संबंधित प्रश्न
Expand 4p2 – 25q2
The product of (x + 5) and (x – 5) is ____________
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
1331x3y – 11y3x
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
(a – b)2 – (b – c)2
Factorise the expression and divide them as directed:
(2x3 – 12x2 + 16x) ÷ (x – 2)(x – 4)
The sum of first n natural numbers is given by the expression `n^2/2 + n/2`. Factorise this expression.
Verify the following:
(m + n)(m2 – mn + n2) = m3 + n3
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
