Advertisements
Advertisements
Question
Evaluate the following, using suitable identity
990 × 1010
Advertisements
Solution
990 × 1010 = (1000 – 10)(1000 + 10)
Taking a = 1000 and b = 10, then
(a – b)(a + b) = a2 – b2 becomes
(1000 – 10)(1000 + 10) = 10002 – 102
990 × 1010 = 1000000 – 100
990 × 1010 = 999900
APPEARS IN
RELATED QUESTIONS
Expand: (3x + 4y)(3x - 4y)
Expand: 102 x 98
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
(5 + 20)(–20 – 5) = ?
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`y^3 - y/9`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2 - y^2/100`
Factorise the expression and divide them as directed:
(3x4 – 1875) ÷ (3x2 – 75)
Verify the following:
(a + b + c)(a2 + b2 + c2 – ab – bc – ca) = a3 + b3 + c3 – 3abc
Verify the following:
(p – q)(p2 + pq + q2) = p3 – q3
Find the value of `(198 xx 198 - 102 xx 102)/96`
