Advertisements
Advertisements
Question
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
Advertisements
Solution
We have, product of two expressions x5 + x3 + x and one is x2 + x + 1.
Let the other expression be A.
Then, A × (x2 + x + 1) = x5 + x3 + x
⇒ `A = (x^5 + x^3 + x)/(x^2 + x + 1)`
= `(x(x^4 + x^2 + 1))/(x^2 + x + 1)`
⇒ `A = (x(x^4 + 2x^2 - x^2 + 1))/(x^2 + x + 1)`
= `(x(x^4 + 2x^2 + 1 - x^2))/(x^2 + x + 1)` ...[Adding and Subtracting x2 in numerator term]
= `(x[(x^4 + 2x^2 + 1) - x^2])/(x^2 + x + 1)`
= `(x[(x^2 + 1)^2 - x^2])/(x^2 + x + 1)`
= `(x(x^2 + 1 + x)(x^2 + 1 - x))/(x^2 + x + 1)` ...[Using the identity, a2 – b2 = (a + b)(a – b)]
= x(x2 + 1 – x)
Hence, the other expression is x(x2 – x + 1).
APPEARS IN
RELATED QUESTIONS
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
9 – 4y2
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
(a + b)(a – b) = a2 – b2
Using suitable identities, evaluate the following.
(9.7)2 – (0.3)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x2 – 9
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
3a2b3 – 27a4b
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(x^3y)/9 - (xy^3)/16`
Factorise the expression and divide them as directed:
(x2 – 22x + 117) ÷ (x – 13)
Factorise the expression and divide them as directed:
(9x2 – 4) ÷ (3x + 2)
