Advertisements
Advertisements
Question
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
25a2 – 49b2
Advertisements
Solution
25a2 – 49b2 = 52a2 – 72b2
= (5a)2 – (7b)2
let a = 5a and b = 7b
a2 – b2 = (a + b)(a – b)
(5a)2 – (7b)2 = (5a + 7b)(5a – 7b)
25a2 – 49b2 = (5a + 7b)(5a – 7b)
APPEARS IN
RELATED QUESTIONS
The difference of the squares, (612 – 512 ) is equal to ______.
Expand 4p2 – 25q2
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
9x2 – 1
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`y^3 - y/9`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
The radius of a circle is 7ab – 7bc – 14ac. Find the circumference of the circle. `(pi = 22/7)`
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
