Advertisements
Advertisements
Question
Find the length of the side of the given square if area of the square is 625 square units and then find the value of x.
Advertisements
Solution
We have, a square having length of a side (4x + 5) units and area is 625 sq.units.
∵ Area of a square = (Side)2
(4x + 5)2 = 625
⇒ (4x + 5)2 = (25)2 ...[Taking square root both sides and neglecting (– ve) sign]
⇒ 4x + 5 = 25
⇒ 4x = 25 – 5
⇒ 4x = 20
⇒ x = 5
Hence, side = 4x + 5 = 4 × 5 + 5 = 25 units
APPEARS IN
RELATED QUESTIONS
Use a suitable identity to get the following products.
(a2 + b2) (− a2 + b2)
Use a suitable identity to get the following products.
`(x/2 + (3y)/4)(x/2 + (3y)/4)`
Using identities, evaluate 8.92
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 5.1 × 5.2
Use the formula to multiply the following.
(x + y) (x − y)
Use the formula to multiply the following.
(a + 6) (a − 6)
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 12x + 36
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 12x + 9
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`9x^2 + 2xy + y^2/9`
The area of a square is given by 4x2 + 12xy + 9y2. Find the side of the square.
