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प्रश्न
Evaluate the following, using suitable identity
51 × 52
बेरीज
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उत्तर
51 × 52 = (50 + 1)(50 + 2)
Taking x = 50, a = 1 and b = 2
Then (x + a)(x + b) = x2 + (a + b)x + ab becomes
(50 + 1)(50 + 2) = 502 + (1 + 2)50 + (1 × 2)
= 2500 + (3)50 + 2
= 2500 + 150 + 2
51 × 52 = 2652
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पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
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