Advertisements
Advertisements
प्रश्न
Evaluate the following, using suitable identity
51 × 52
बेरीज
Advertisements
उत्तर
51 × 52 = (50 + 1)(50 + 2)
Taking x = 50, a = 1 and b = 2
Then (x + a)(x + b) = x2 + (a + b)x + ab becomes
(50 + 1)(50 + 2) = 502 + (1 + 2)50 + (1 × 2)
= 2500 + (3)50 + 2
= 2500 + 150 + 2
51 × 52 = 2652
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
APPEARS IN
संबंधित प्रश्न
Expand.
`(x + 1/x)(x - 1/x)`
Expand.
`(1/y + 4)(1/y - 9)`
Use the Identity (x + a)(x + b) = x2 + (a + b)x + ab to find the following:
501 × 502
Expand: (x + 2)(x + 3).
Expand: (y + 4)(y - 3)
Expand: `(m + 3/2)(m + 1/2)`.
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(x + 3)(x + 7)
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(6a + 9)(6a – 5)
Simplify using identities
(3p + q)(3p + r)
Using suitable identities, evaluate the following.
104 × 97
