Advertisements
Advertisements
प्रश्न
Expand (2n – 1)(2n + 3)
बेरीज
Advertisements
उत्तर
(2n – 1)(2n + 3)
Comparing (2n – 1)(2n + 3) with (x + a)(x + b) we have a = –1, b = 3
(x + a)(x + b) = x2 + (a + b)x + ab
(2n + (–1))(2n + 3) = (2n)2 + (–1 + 3)2n + (–1)(3)
= 22n2 + 2(2n) – 3
= 4n2 + 4n – 3
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.3 [पृष्ठ ९१]
APPEARS IN
संबंधित प्रश्न
Expand.
(m − 4)(m + 6)
Expand.
(p + 8) (p − 3)
Expand.
(9x − 5t) (9x + 3t)
Expand.
`(m + 2/3)(m − 7/3)`
Expand.
`(x + 1/x)(x - 1/x)`
Use the Identity (x + a) (x + b) = x2 + (a + b)x + ab to find the following:
95 × 103
Expand: `(m + 3/2)(m + 1/2)`.
Expand: (x - 3)(x - 7).
Using suitable identities, evaluate the following.
101 × 103
The following expression is the area of a rectangle. Find the possible length and breadth of the rectangle.
x2 – 6x + 8
