Question

The solution of which of the following equations is neither a fraction nor an integer?

Options

• 2x + 6 = 0

• 3x – 5 = 0

• 5x – 8 = x + 4

• 4x + 7 = x + 2

Answer 1

4x + 7 = x + 2

Explanation:

Let us solve the equations:

a. Given equation is 2x + 6 = 0

⇒ 2x = –6  ...[Transposing 6 to RHS]

⇒ x = `-6/2`  ...[Dividing both sides by 2]

⇒ x = –3  ...(Integer)

b. Given equation is 3x – 5 = 0

⇒ 3x = 5  ...[Transposing 5 to RHS]

⇒ k = `5/3`(fraction)  ...[Dividing both sides by 3]

c. Given equation is 5x – 8 = x + 4

⇒ 5x = x + 4 + 8  ...[Transposing 8 to RHS]

⇒ 5x = x + 12  

⇒ 5x – x + 12  ...[Transposing x to LHS]

⇒ 4x = 12

⇒ x = 3  (Integer)  ...[dividing both sides by 4]

d. Given equation is 4x + 7 = x + 2

⇒ 4x + 7 – x + 2  ...[Transposing x to LHS]

⇒ 3x = 2 – 7  ...[Transposing 7 to RHS]

⇒ 3x = –5

⇒ x = `-5/3`  ...[Dividing both sides by 3]

Which is neither a positive fraction nor an integer.