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Question
The solution of which of the following equations is neither a fraction nor an integer?
Options
2x + 6 = 0
3x – 5 = 0
5x – 8 = x + 4
4x + 7 = x + 2
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Solution
4x + 7 = x + 2
Explanation:
Let us solve the equations:
a. Given equation is 2x + 6 = 0
⇒ 2x = –6 ...[Transposing 6 to RHS]
⇒ x = `-6/2` ...[Dividing both sides by 2]
⇒ x = –3 ...(Integer)
b. Given equation is 3x – 5 = 0
⇒ 3x = 5 ...[Transposing 5 to RHS]
⇒ k = `5/3`(fraction) ...[Dividing both sides by 3]
c. Given equation is 5x – 8 = x + 4
⇒ 5x = x + 4 + 8 ...[Transposing 8 to RHS]
⇒ 5x = x + 12
⇒ 5x – x + 12 ...[Transposing x to LHS]
⇒ 4x = 12
⇒ x = 3 (Integer) ...[dividing both sides by 4]
d. Given equation is 4x + 7 = x + 2
⇒ 4x + 7 – x + 2 ...[Transposing x to LHS]
⇒ 3x = 2 – 7 ...[Transposing 7 to RHS]
⇒ 3x = –5
⇒ x = `-5/3` ...[Dividing both sides by 3]
Which is neither a positive fraction nor an integer.
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| (iii) `x/12 = -5` | (C) 4 |
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| (G) 3 |
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