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प्रश्न
The solution of which of the following equations is neither a fraction nor an integer?
पर्याय
2x + 6 = 0
3x – 5 = 0
5x – 8 = x + 4
4x + 7 = x + 2
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उत्तर
4x + 7 = x + 2
Explanation:
Let us solve the equations:
a. Given equation is 2x + 6 = 0
⇒ 2x = –6 ...[Transposing 6 to RHS]
⇒ x = `-6/2` ...[Dividing both sides by 2]
⇒ x = –3 ...(Integer)
b. Given equation is 3x – 5 = 0
⇒ 3x = 5 ...[Transposing 5 to RHS]
⇒ k = `5/3`(fraction) ...[Dividing both sides by 3]
c. Given equation is 5x – 8 = x + 4
⇒ 5x = x + 4 + 8 ...[Transposing 8 to RHS]
⇒ 5x = x + 12
⇒ 5x – x + 12 ...[Transposing x to LHS]
⇒ 4x = 12
⇒ x = 3 (Integer) ...[dividing both sides by 4]
d. Given equation is 4x + 7 = x + 2
⇒ 4x + 7 – x + 2 ...[Transposing x to LHS]
⇒ 3x = 2 – 7 ...[Transposing 7 to RHS]
⇒ 3x = –5
⇒ x = `-5/3` ...[Dividing both sides by 3]
Which is neither a positive fraction nor an integer.
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संबंधित प्रश्न
Solve the following equations.
`(2b)/3 - 5 = 3`
Solve the following equations.
4(2 - x) = 8
Which of the following is not allowed in a given equation?
If 2x + 3 = 5, then value of 3x + 2 is ______.
x – 0 = ______; when 3x = 12.
x – ______ = 15; when `x/2` = 6.
The solution of the equation x + 15 = 19 is ______.
4x – 5 = 7 does not have an integer as its solution.
`3/2` is the solution of the equation 8x – 5 = 7.
If 4x – 7 = 11, then x = 4.
