Advertisements
Advertisements
Question
The simplest rationalising factor of \[2\sqrt{5}-\]\[\sqrt{3}\] is
Options
\[2\sqrt{5} + 3\]
\[2\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} - \sqrt{3}\]
Advertisements
Solution
We know that rationalization factor for `asqrtb - sqrtc` is .`asqrtb +sqrtc` Hence rationalization factor of `2sqrt5-sqrt3`
APPEARS IN
RELATED QUESTIONS
Assuming that x, y, z are positive real numbers, simplify the following:
`(x^-4/y^-10)^(5/4)`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
`(2/3)^x (3/2)^(2x)=81/16 `then x =
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
The simplest rationalising factor of \[\sqrt[3]{500}\] is
Find:-
`16^(3/4)`
