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Karnataka Board PUCPUC Science 2nd PUC Class 12

The partial pressure of ethane over a solution containing 6.56 × 10^−3 g of ethane is 1 bar. If the solution contains 5.00 × 10^−2 g of ethane, then what shall be the partial pressure of the gas?

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Question

The partial pressure of ethane over a solution containing 6.56 × 10−3 g of ethane is 1 bar. If the solution contains 5.00 × 10−2 g of ethane, then what shall be the partial pressure of the gas?

Numerical
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Solution

According to Henry’s law,

m = kP

For the first case,

6.56 × 10−3 = k × 1    ...(i)

For the second case,

5 × 10−2 = k × p    ...(ii)

Dividing eq. (i) by eq. (ii), we get

`(6.56 xx 10^-3)/(5 xx 10^-2) = (k xx 1)/(k xx p) = 1/p`

∴ p = `(5 xx 10^-2)/(6.56 xx 10^-3)`

= 7.62 bar

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Chapter 1: Solutions - Exercises [Page 28]

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NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 1 Solutions
Exercises | Q 1.13 | Page 28
Nootan Chemistry [English] Class 12 ISC
Chapter 1 Solutions
'NCERT TEXT-BOOK' Exercises | Q 2.13 | Page 124

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