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Question
Assume that argon exerts a partial pressure of 6 bar. Calculate the solubility of argon gas in water. (Given Henry’s law constant for argon dissolved in water, KH = 40 k bar)
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Solution
p = KHx
Mole fraction of argon in water x = `"p"/"k"`
= `6/40 × 10^3`
= 1.5 × 10–4
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