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The given figure is a cross -section of a victory stand used in sports. All measurements are in centimetres. Assume all angles in the figure are right angles. If the width of the stand is 60 cm, fin

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Question

The given figure is a cross -section of a victory stand used in sports. All measurements are in centimetres. Assume all angles in the figure are right angles. If the width of the stand is 60 cm, find The space it occupies in cm3.

Sum
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Solution


To find the volume, first find the area of the figure.
To find the area, we divide the figure into 3 different rectangles.
Rectangle 1 (left):
length = 50cm
width = 40cm
Area = length x width
= 50 x 40
= 2000cm2
Rectangle 2 (middle):
length = (60 + 30)cm = 90cm
width = 40cm
Area = length x width
= 90 x 40
= 3600cm2
Rectangle 3 (right):
length = 60cm
width = 40cm
Area = length x width
= 60 x 40
= 2400cm2
Total area
= 2000 + 3600 + 2400
= 8000cm2
Volume = Total area x length
= 8000 x 60
= 4,80,000cm3
∴ The space occupied is 4,80,000cm3.

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Cross Section of Solid Shapes
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Chapter 20: Surface Areas and Volume of Solids - Exercise 25.3

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Frank Mathematics Part 1 [English] Class 9 ICSE
Chapter 20 Surface Areas and Volume of Solids
Exercise 25.3 | Q 3.1
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