English

A School Auditorium is 40 M Long, 30 M Broad and 12 M High. If Each Student Requires 1.2 M2 of the Floor Area; Find the Maximum Number of Students that Can Be Accommodated in this Auditorium

Advertisements
Advertisements

Question

A school auditorium is 40 m long, 30 m broad and 12 m high. If each student requires 1.2 m2 of the floor area; find the maximum number of students that can be accommodated in this auditorium. Also, find the volume of air available in the auditorium, for each student. 

Sum
Advertisements

Solution

Given dimensions of the auditorium are: 40 m x 30 m x 12 m

The area of the floor = 40 x 30

Also given that each student requires 1.2 m2 of the floor area. 

Thus, Maximum number of students = ` (40 xx 30 )/(1.2 )= 1000`

Volume of the auditorium
= 40 x 30 x 12 m3 
= Volume of air available forr 1000 students

Therefore, Air available for each students
=`( 40 xx 30 xx12 )/( 1000 )"m"^3 = 14.4 "m"^3`

shaalaa.com
Cross Section of Solid Shapes
  Is there an error in this question or solution?
Chapter 21: Solids [Surface Area and Volume of 3-D Solids] - Exercise 21 (C) [Page 274]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Solids [Surface Area and Volume of 3-D Solids]
Exercise 21 (C) | Q 2 | Page 274

RELATED QUESTIONS

The following figure shows a solid of uniform cross-section. Find the volume of the solid. All measurements are in centimeters.

Assume that all angles in the figures are right angles.


A swimming pool is 40 m long and 15 m wide. Its shallow and deep ends are 1.5 m and 3 m deep respectively. If the bottom of the pool slopes uniformly, find the amount of water in liters required to fill the pool.


A rectangular field is 112 m long and 62 m broad. A cubical tank of edge 6 m is dug at each of the four corners of the field and the earth so removed is evenly spread on the remaining field. Find the rise in level.  


The figure represents the cross section of a swimming pool 10 m broad, 2 m deep at one end, 3 m deep at the other end. Calculate the volume of water it will hold when full, given that its length is 40 m.


The given figure is a cross -section of a victory stand used in sports. All measurements are in centimetres. Assume all angles in the figure are right angles. If the width of the stand is 60 cm, find The total surface area in m2.


A swimming pool is 50 m long and 15 m wide. Its shallow and deep ends are 1.5 m and 4.5 m respectively. If the bottom of the pool slopes uniformly, find the amount of water in kilolitres required to fill the pool (1 m3 = 1000 liters).


The figure shows the cross section of 0.2 m a concrete wall to be constructed. It is 0.2 m wide at the top, 2.0 m wide at the bottom and its height is 4.0 m, and its length is 40 m. Calculate the cross sectional area


The figure shows the cross section of 0.2 m a concrete wall to be constructed. It is 0.2 m wide at the top, 2.0 m wide at the bottom and its height is 4.0 m, and its length is 40 m. If the whole wall is to be painted, find the cost of painting it at 2.50 per sq m.


The cross section of a tunnel perpendicular to its length is a trapezium ABCD as shown in the figure. AM = BN; AB = 4.4 m, CD = 3 m The height of a tunnel is 2.4 m. The tunnel is 5.4 m long. Calculate the cost of painting the internal surface of the tunnel (excluding the floor) at the rate of Rs. 5 per m2.


The cross section of a canal is a trapezium with the base length of 3 m and the top length of 5 m. It is 2 m deep and 400 m long. Calculate the volume of water it holds.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×