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The given figure is a cross -section of a victory stand used in sports. All measurements are in centimetres. Assume all angles in the figure are right angles. If the width of the stand is 60 cm, fin

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Question

The given figure is a cross -section of a victory stand used in sports. All measurements are in centimetres. Assume all angles in the figure are right angles. If the width of the stand is 60 cm, find The total surface area in m2.

Sum
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Solution

Total surface area = 2 x Area of cross section + Area of bottom face + Area of left face + Area of right face + Area of top face
Area of Cross-section = 8000cm2  ...(from a)
Width of the stand = 60cm  ...(given)
Area of bottom face 
= 130 x 60
= 7800cm2
Area of the left face
= 40 x 60 + 50 x 60 + 50 x 60
= 8400cm2
Area of right face
= 60 x 60 + 40 x 60 + 30 x 60
= 7800cm2
Area of the top face
= 40 x 60
= 2400cm2
Total surface area
= 2 x 8000 + 7800 + 8400 + 7800 + 2400
= 42400cm2
= 4.24m2
∴ The total surface area is 4.24m2.

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Cross Section of Solid Shapes
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Chapter 20: Surface Areas and Volume of Solids - Exercise 25.3

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Frank Mathematics Part 1 [English] Class 9 ICSE
Chapter 20 Surface Areas and Volume of Solids
Exercise 25.3 | Q 3.2

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